# Multiple Choice Questions (MCQ) on Flywheel

**1. The radius of gyration of a solid disc type flywheel of diameter ‘D’ is**

a. D b. D/2 c. D/√2 d. (√3/2)D

**2. With usual notations for different parameters involved, the maximum fluctuations of energy for a flywheel is given by**

a. 2EC_{S} b. EC_{S}/2 c. 2EC_{S}^{2} d. 2E^{2}C_{S}

(Ans:a)

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** 3. Turning moment diagram is a graph between**

a.** **Torque and Crank angle b. Torque and crank radius

c. Force and crank radius d. none of the above

(Ans: a)

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**4. Mean resisting torque in Turning Moment diagram is given by**

a. Work done per cycle/Angle turned during the cycle

b. Work done per cycle x Angle during the cycle

c. Work done per revolution /Angle during the cycle

d. None of the above

(Ans: a)

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**5. The energy is stored in Flywheel in form of**

a. Potential energy b. Kinetic energy c. Heat energy d. Electrical energy

(Ans: b)

**6. The radius of Gyration (k) for Rim Type Flywheel having radius ‘r’ is given by**

a. k = 2r b. k=r/2 c. k=r d. k=r/3

(Ans: c)

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**7. The coefficient of fluctuation of speed of Flywheel is given by**

a. (N_{1}-N_{2})/N b. (N_{1}+N_{2})/N c. (N_{1}-N_{2}) x N b. (N_{1}+N_{2}) x N

Where N_{1} =Maximum speed, N_{2} = Minimum speed, N = Mean speed.

(Ans: a)

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**8. The Coefficient of fluctuation of energy of flywheel is given as**

a. (E_{max }– E_{min})/Work done per cycle b. (E_{max }+ E_{min})/Work done per cycle

c. (E_{max }– E_{min}) x Work done per cycle d. (E_{max }+ E_{min}) x Work done per cycle

Where E_{max }= Maximum Kinetic energy of the Flywheel.

E_{min} = Minimum Kinetic energy of the Flywheel

(Ans: a)