Multiple Choice Questions (MCQ) on Simple stress and strain
Modulus of rigidity is
- Tensile stress / Tensile strain
- Shear stress / Shear strain
- Tensile stress / Shear strain
- Shear stress / Tensile strain
(Ans:b)
Bulk modulus of elasticity is
- Tensile stress / Tensile strain
- Shear stress / Shear strain
- Tensile stress / Shear strain
- Normal stress on each face of cube / Volumetric strain
(Ans:d)
Factor of safety is
- Tensile stress / Permissible stress
- Compressive stress / Ultimate stress
- Ultimate stress / Permissible stress
- Ultimate stress / Shear stress
(Ans:c)
Poisson’s ratio is
- Lateral strain / Longitudinal strain
- Shear strain / Lateral strain
- Longitudinal strain / Lateral strain
- Lateral strain / Volumetric strain
(Ans:a)
A rod, 120cm long and of diameter 3.0 cm is subjected to an axial pull of 18 kN. The stress in N/mm2 is.
- 22.57
- 23.47
- 24.57
- 25.47
(Ans:d)
The total extension in a bar, consists of 3 bars of same material, of varying sections is
- P/E(L1/A1+L2/A2+L3/A3)
- P/E(L1A1+L2A2+L3A3)
- PE(L1/A1+L2/A2+L3/A3)
- PE(L1/A1+L2/A2+L3/A3)
Where P=Load applied, E=young’s modulus for the bar, L1,2,3=Length of corresponding bars, A1,2,3=Area of corresponding bars
(Ans:a)
The relationship between Young’s modulus (E), Bulk modulus (K) and Poisson’s ratio (µ) is given by
- E=2K(1-2µ)
- E=3K(1-2µ)
- E=2K(1-2µ)
- E=2K(1-3µ)
(Ans:b)
The relationship between Young’s modulus (E), Modulus of rigidity (C) and Bulk modulus (K) is given by
- E=9CK/(C+3K)
- E=9CK/(2C+3K)
- E=9CK/(3C+K)
- E=9CK/(C-3K)
(Ans:a)
The total extension of a taper rod of length ‘L’ and end diameters ‘D1’ and ‘D2’, subjected to a load (P), is given of
- 4PL/ΠE. D1D2
- 3PL/ΠE. D1D2
- 2PL/ΠE. D1D2
- PL/ΠE.D1D2
Where E=Young’s modulus of elasticity
(Ans:a)
A rod 3 m long is heated from 10°C to 90°C. Find the expansion of rod. Take Young’s modulus = 1.0 x 10^5 MN/m2 and coefficient of thermal expansion = 0.000012 per degree centigrade.
- 0.168 cm
- 0.208 cm
- 0.288 cm
- 0.348 cm
(Ans:c)
Elongation of a bar of uniform cross section of length ‘L’, due to its own weight ‘W’ is given by
- 2WL/E
- WL/E
- WL/2E
- WL/3E
Where, E=Young’s modulus of elasticity of material
(Ans:c)